- I suppose that algae does not differentiate between Sweden, Latvia or other nations, as it is driven by the wind.
- Jag antar att alger inte skiljer sig åt mellan Sverige, Lettland eller andra länder eftersom de sprids med vinden.
- We are duty bound to assist the citizens of Europe to differentiate between good food and food that might not comply with European standards.
- Vi har en skyldighet att hjälpa EU-medborgarna att skilja mellan bra livsmedel och livsmedel som kanske inte uppfyller EU:s standarder.
- we have had an enormous lobby in this European Parliament from the organizations representing the blind, who want to be able to clearly differentiate between one denomination of a coin and another.
- Vi har haft en enorm lobby i detta Europaparlament från organisationer som representerar blinda, som lätt vill kunna skilja mellan de olika mynten.
- Moreover, the notifications of seizures by the Member States do not always differentiate between genuine and counterfeit cigarettes, partly because it is not necessary for the purposes of the prosecution of offenders and the collection of duties and taxes and partly because it is sometimes extremely difficult to distinguish between counterfeit and genuine cigarettes.
- Medlemsstaternas rapporter om beslagtagande skiljer inte alltid mellan äkta och förfalskade cigaretter, delvis eftersom detta inte är nödvändigt för att åtala förbrytarna och för inkassering av tull och skatter och delvis eftersom det ibland är extremt svårt att skilja mellan förfalskade och äkta cigaretter.
show query
SET search_path TO f9miniensv;
WITH
list AS (SELECT
t11.token_id AS t11,
t12.token_id AS t12,
t21.token_id AS t21,
t22.token_id AS t22,
r1.dep_id AS dep1,
r2.dep_id AS dep2
FROM
deprel r1
JOIN depstr s1 ON s1.dep_id = r1.dep_id
JOIN word_align a1 ON a1.wsource = r1.head AND a1.wsource < a1.wtarget
JOIN word_align a2 ON a2.wsource = r1.dependent
JOIN deprel r2 ON r2.head = a1.wtarget AND r2.dependent = a2.wtarget
JOIN depstr s2 ON s2.dep_id = r2.dep_id
JOIN token t11 ON t11.token_id = r1.head
JOIN token t21 ON t21.token_id = r2.head
JOIN token t12 ON t12.token_id = r1.dependent
JOIN token t22 ON t22.token_id = r2.dependent
WHERE
s1.val = 'prep' AND
t11.ctag = 'VERB' AND
t21.ctag = 'VERB' AND
t12.ctag = 'ADP' AND
t22.ctag = 'ADP' AND
t11.lemma_id = 61514 AND
t12.lemma_id = 53533 AND
t21.lemma_id = 7078 AND
t22.lemma_id = 469),
stats AS (SELECT
sentence_id,
count(DISTINCT token_id) AS c,
count(*) AS c_aligned,
count(DISTINCT wtarget) AS c_target
FROM
token
LEFT JOIN word_align ON wsource = token_id
WHERE
sentence_id IN (
SELECT sentence_id
FROM
list
JOIN token ON token_id IN(t11, t21)
)
GROUP BY sentence_id),
numbered AS (SELECT row_number() OVER () AS i, *
FROM
list),
sentences AS (SELECT *, .2 * (1 / (1 + exp(max(c) OVER (PARTITION BY i) - min(c) OVER (PARTITION BY i)))) +
.8 * (1 / log(avg(c) OVER (PARTITION BY i))) AS w
FROM
(
SELECT i, 1 AS n, sentence_id, ARRAY[t11,t12] AS tokens
FROM
numbered
JOIN token ON token_id = t11
UNION SELECT i, 2 AS n, sentence_id, ARRAY[t21,t22] AS tokens
FROM
numbered
JOIN token ON token_id = t21
) x
JOIN stats USING (sentence_id)
ORDER BY i, n)
SELECT
i,
n,
w,
c,
c_aligned,
c_target,
sentence_id,
string_agg(CASE WHEN lpad THEN ' ' ELSE '' END || '<span class="token' ||
CASE WHEN ARRAY[token_id] <@ tokens THEN ' hl' ELSE '' END || '">' || val || '</span>',
'' ORDER BY token_id ASC) AS s
FROM
sentences
JOIN token USING (sentence_id)
JOIN typestr USING (type_id)
GROUP BY i, n, w, c, c_aligned, c_target, sentence_id
ORDER BY w DESC, i, n;
;