- If the European Union wants to be the world’s most competitive region, that means that its enterprises must be the most competitive enterprises in the world.
- Om Europeiska unionen vill bli världens mest konkurrenskraftiga region, så innebär det att dess företag måste bli de mest konkurrenskraftiga företagen i världen.
- We have jointly - and ambitiously - resolved that the European Union is to become the world’s most competitive region within the next ten years.
- … har vi ju gemensamt bestämt oss för - det är en ambitiös plan - att Europeiska unionen inom de närmaste tio åren skall bli världens mest konkurrenskraftiga region.
- It is, therefore, very important for national egoisms to be genuinely transformed into a sense of national responsibility and also a sense of responsibility at the European level, because unless we address the issue of harmonising social policy and harmonising tax policy as soon as possible, it will not be possible to fulfil the objectives of economic policy or of our common European economy which will turn us into a genuinely competitive region in a globalised world.
- Därför är det mycket viktigt att nationell egoism verkligen omvandlas i en känsla av nationellt ansvar och en känsla av ansvar på EU-nivå, för om vi inte tar itu med frågan om en harmonisering av socialpolitiken och av skattepolitiken så snart som möjligt kommer vi inte att kunna uppfylla de målsättningar inom den ekonomiska politiken eller inom vår gemensamma europeiska politik som kommer att göra oss till en verkligt konkurrenskraftig region i en globaliserad värld.
show query
SET search_path TO f9miniensv;
WITH
list AS (SELECT
t11.token_id AS t11,
t12.token_id AS t12,
t21.token_id AS t21,
t22.token_id AS t22,
r1.dep_id AS dep1,
r2.dep_id AS dep2
FROM
deprel r1
JOIN depstr s1 ON s1.dep_id = r1.dep_id
JOIN word_align a1 ON a1.wsource = r1.head AND a1.wsource < a1.wtarget
JOIN word_align a2 ON a2.wsource = r1.dependent
JOIN deprel r2 ON r2.head = a1.wtarget AND r2.dependent = a2.wtarget
JOIN depstr s2 ON s2.dep_id = r2.dep_id
JOIN token t11 ON t11.token_id = r1.head
JOIN token t21 ON t21.token_id = r2.head
JOIN token t12 ON t12.token_id = r1.dependent
JOIN token t22 ON t22.token_id = r2.dependent
WHERE
s1.val = 'amod' AND
s2.val = 'AT' AND
t11.ctag = 'NOUN' AND
t21.ctag = 'NOUN' AND
t12.ctag = 'ADJ' AND
t22.ctag = 'ADJ' AND
t11.lemma_id = 43161 AND
t12.lemma_id = 37762 AND
t21.lemma_id = 43161 AND
t22.lemma_id = 33705),
stats AS (SELECT
sentence_id,
count(DISTINCT token_id) AS c,
count(*) AS c_aligned,
count(DISTINCT wtarget) AS c_target
FROM
token
LEFT JOIN word_align ON wsource = token_id
WHERE
sentence_id IN (
SELECT sentence_id
FROM
list
JOIN token ON token_id IN(t11, t21)
)
GROUP BY sentence_id),
numbered AS (SELECT row_number() OVER () AS i, *
FROM
list),
sentences AS (SELECT *, .2 * (1 / (1 + exp(max(c) OVER (PARTITION BY i) - min(c) OVER (PARTITION BY i)))) +
.8 * (1 / log(avg(c) OVER (PARTITION BY i))) AS w
FROM
(
SELECT i, 1 AS n, sentence_id, ARRAY[t11,t12] AS tokens
FROM
numbered
JOIN token ON token_id = t11
UNION SELECT i, 2 AS n, sentence_id, ARRAY[t21,t22] AS tokens
FROM
numbered
JOIN token ON token_id = t21
) x
JOIN stats USING (sentence_id)
ORDER BY i, n)
SELECT
i,
n,
w,
c,
c_aligned,
c_target,
sentence_id,
string_agg(CASE WHEN lpad THEN ' ' ELSE '' END || '<span class="token' ||
CASE WHEN ARRAY[token_id] <@ tokens THEN ' hl' ELSE '' END || '">' || val || '</span>',
'' ORDER BY token_id ASC) AS s
FROM
sentences
JOIN token USING (sentence_id)
JOIN typestr USING (type_id)
GROUP BY i, n, w, c, c_aligned, c_target, sentence_id
ORDER BY w DESC, i, n;
;