- We have no judgement of what we define as a common difficulty, a common challenge, and we have no idea of a common approach.
- Vi har ingen uppfattning om vad vi definierar som gemensam svårighet eller gemensam utmaning och vi har inget begrepp om vad som är ett gemensamt angreppssätt.
- We must also make it clear that the social agenda does not intend to impose a uniform social policy but to coordinate, support and boost national policies within a global framework for social development, because all Member States currently face common challenges, which are naturally of varying proportions, such as working structures, discrimination against citizens and gender inequalities.
- Anledningen till detta är att medlemsstaterna i dagsläget har att bemöta gemensamma utmaningar, naturligtvis av olika stora dimensioner, som t.ex. arbetsstrukturerna, diskriminering gentemot medborgare samt de två könens jämställdhet.
- Consequently, the common challenge that Community policies and the various national governments face is to ensure that the main mechanisms for the distributive effects of the labour market - the tax system, social security, education, housing, health and other public services - become sufficiently universal to respond to the needs of those who are most exposed to the risks of poverty and social exclusion.
- Så den gemensamma utmaningen som gemenskapspolitiken och de olika nationella regeringarna har är att garantera att de främsta fördelningsmekanismerna för möjligheter och resurser - en arbetsmarknad för alla, med kvalitativa arbeten för kvinnor, skattesystemen, socialförsäkringssystemet, utbildningssystemet, bostäder, hälsovård och där andra offentliga tjänster ingår - blir tillräckligt allmänna för att kunna svara på behoven hos de personer som är mest utsatta för fattigdom och social utslagning.
show query
SET search_path TO f9miniensv;
WITH
list AS (SELECT
t11.token_id AS t11,
t12.token_id AS t12,
t21.token_id AS t21,
t22.token_id AS t22,
r1.dep_id AS dep1,
r2.dep_id AS dep2
FROM
deprel r1
JOIN depstr s1 ON s1.dep_id = r1.dep_id
JOIN word_align a1 ON a1.wsource = r1.head AND a1.wsource < a1.wtarget
JOIN word_align a2 ON a2.wsource = r1.dependent
JOIN deprel r2 ON r2.head = a1.wtarget AND r2.dependent = a2.wtarget
JOIN depstr s2 ON s2.dep_id = r2.dep_id
JOIN token t11 ON t11.token_id = r1.head
JOIN token t21 ON t21.token_id = r2.head
JOIN token t12 ON t12.token_id = r1.dependent
JOIN token t22 ON t22.token_id = r2.dependent
WHERE
s1.val = 'amod' AND
s2.val = 'AT' AND
t11.ctag = 'NOUN' AND
t21.ctag = 'NOUN' AND
t12.ctag = 'ADJ' AND
t22.ctag = 'ADJ' AND
t11.lemma_id = 19851 AND
t12.lemma_id = 42586 AND
t21.lemma_id = 49451 AND
t22.lemma_id = 41367),
stats AS (SELECT
sentence_id,
count(DISTINCT token_id) AS c,
count(*) AS c_aligned,
count(DISTINCT wtarget) AS c_target
FROM
token
LEFT JOIN word_align ON wsource = token_id
WHERE
sentence_id IN (
SELECT sentence_id
FROM
list
JOIN token ON token_id IN(t11, t21)
)
GROUP BY sentence_id),
numbered AS (SELECT row_number() OVER () AS i, *
FROM
list),
sentences AS (SELECT *, .2 * (1 / (1 + exp(max(c) OVER (PARTITION BY i) - min(c) OVER (PARTITION BY i)))) +
.8 * (1 / log(avg(c) OVER (PARTITION BY i))) AS w
FROM
(
SELECT i, 1 AS n, sentence_id, ARRAY[t11,t12] AS tokens
FROM
numbered
JOIN token ON token_id = t11
UNION SELECT i, 2 AS n, sentence_id, ARRAY[t21,t22] AS tokens
FROM
numbered
JOIN token ON token_id = t21
) x
JOIN stats USING (sentence_id)
ORDER BY i, n)
SELECT
i,
n,
w,
c,
c_aligned,
c_target,
sentence_id,
string_agg(CASE WHEN lpad THEN ' ' ELSE '' END || '<span class="token' ||
CASE WHEN ARRAY[token_id] <@ tokens THEN ' hl' ELSE '' END || '">' || val || '</span>',
'' ORDER BY token_id ASC) AS s
FROM
sentences
JOIN token USING (sentence_id)
JOIN typestr USING (type_id)
GROUP BY i, n, w, c, c_aligned, c_target, sentence_id
ORDER BY w DESC, i, n;
;